Strength of acidity is in order :

I I > I

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I > I I

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I = I I

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cannot be determined

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Solution

The correct option is C $I > I I$
Solution:-

As we know that the strength of acidity inversely depends upon the $+ I$ effect.

Thus, due to $+ I$ effect of methyl group $(- C H_{3})$ , $I$ is more acidic than $I I$ .

Hence the correct order of strength of acidity is-
$I > I I$

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Similar questions

Q. Arrange the following oxides in the decreasing order of their acidic strengths.

I . Z n O

I I . K_{2} O

I I I . P_{2} O_{5}

I V . M g O

In the following molecules:
$B F_{3}, B C l_{3}, B B r_{3}, B I_{3} I, I I, I I I, I V$
The correct order of Lewis acidic strength will be:

Mark the correct order of decreasing acid strength of the following compounds.

(a) V > IV > II > I > III
(b) II > IV > I > III > V
(c) IV > V > III > II > I
(d) V > IV > III > II > I

Q. Arrange

O H C H_{2} C O O H (I),

H O C H_{2} C H_{2} C O O H (I I)

and

C H_{3} C O O H (I I I)

in order of their acidic strength.

Q. The decreasing order of acidity of the following compounds is:

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Strength of acidity is in order :

The correct option is C I>IISolution:-As we know that the strength of acidity inversely depends upon the +I effect.Thus, due to +I effect of methyl group (−CH3), I is more acidic than II.Hence the correct order of strength of acidity is-I>II

The correct option is C $I > I I$
Solution:-

As we know that the strength of acidity inversely depends upon the $+ I$ effect.

Thus, due to $+ I$ effect of methyl group $(- C H_{3})$ , $I$ is more acidic than $I I$ .

Hence the correct order of strength of acidity is-
$I > I I$