Question

Stress generated in a wire when force $F_1$ acts on it as shown in the figure, is $T$. Initial cross sectional area of the wire is $A_1$. When force $F_2$ replaces $F_1$, cross-sectional area becomes $A_2$. Find $\left(\frac{A_2}{A_1}\right)$ if $F_2=6\text{N}$.
[Consider stress generated in the wire to be the same]

• A. $3$
• B. $1/2$
• C. $4$
• D. $1/6$

Answer 1

The correct option is A $3$

Given,
Stress generated in the wire is same in both cases.
$\text{Stress generated when}{F}_1\text{acts = Stress generated when}{F}_2\text{acts}$

$\Rightarrow \frac{F_1}{A_1}=\frac{F_2}{A_2}$
$\Rightarrow \frac{2}{A_1}=\frac{6}{A_2}$
$\Rightarrow \frac{A_2}{A_1}=\frac{6}{2}=3$