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Question

Strings of same material but lengths I and 2I have radii 2r and r respectively. They are stretched under the same tension. Both the strings vibrate in their fundamental modes, the one of the length vibrates with frequency n1 and the other with frequency n2. The ratio of n1n2 is given by:

A
2
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B
4
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C
8
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D
1
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Solution

The correct option is D 1
n=v2l=Tμ2l, where μ = mass per unit length =ρs
or n=12lTρs, but s=πr2
n1rl
or n1n2=r2l2r1l1=r×2l2r×l=1

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