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30 ml of 0.25...

Question

30 ml of 0.25M sulphuric acid is diluted to 100 ml by adding distilled water . calculate the molarity of the resultant solution

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Solution

$A c c o r d i n g t o v o l u m e t r i c p r i n c i p l e V_{1} M_{1} = V_{2} M_{2} 30 \times 0.25 = 100 \times M_{2} M_{2} = \frac{30 \times 0.25}{100} = 0.075 M$

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