A mica sheet has a thickness equal to the separation between the two plates of a parallel plate air capacitor. How would the capacitance change if the mica sheet
Is partially introduced in the space between the plates,

Occupies the whole intermediate space?

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Solution

Dear Student ,
When the mica sheet is partially introduced then the capacitance of the capacitor increases .
But when the mica sheet is introduced whole in the space between the plates then the d = t , where d is the distance between the plates and t is the thickness of the mica sheet .
Now look if we introduce the mica sheet wholly then the capacitance will be ,
$C = \frac{α}{4 π [d - (t - t / k)]} N o w w h e n d = t t h e n, C = \frac{α k}{4 π t} . S o t h e c a p a c i \tan c e h e r e d e c r e a s e s .$
Regards

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A parallel plate capacitor with air between the plates has a capacitance of $9 p F$ . The separation between its plates is $d$ . The space between the plate is now partially filled with two dielectrics. One of the dielectric has dielectric constant $K_{1} = 3$ and thickness $\frac{d}{3}$ while the other one has dielectric constant $K_{2} = 6$ and thickness $\frac{d}{3}$ . The remaining $\frac{d}{3}$ space is filled with air. The new capacitance is :