Question

A train moving at a speed of 180 km/h comes to a stop at constant acceleration in 15 minutes after covering the distance of 2 km.
What is the acceleration of the train?

Answer 1

Dear student
$$\begin{gathered} velocity \\ u=180km/hr=180\times \frac{5}{18}=50m/s \\ applyingtheformula \\ {v}^2-u^2=2as \\ {0}^2-{50}^2=-2\times a\times 2000 \\ a=\frac{2500}{4000}=\frac{25}{40}=\frac{5}{8}=0.625m/s^2 \\ Regards \end{gathered}$$