Question

​AT A CAMP THERE IS ENOUGH FOOD FOR 156 SCOUTS FOR 15 DAYS.
1)HOW MANY DAYS THE FOOD WILL LAST IF 39 MORE SCOUTS ARE ADDED.
​2)HOW MANY SCOUTS SHOULD GO IF THE FOOD IS TO BE LAST FOR 26 DAYS.

Answer 1

Dear student,
Here is the solution of your asked query:
$$\begin{gathered} \mathrm{Number}\mathrm{of}\mathrm{scouts}=156 \\ \mathrm{Number}\mathrm{of}\mathrm{days}=15 \\ \mathrm{So},\mathrm{Food}\mathrm{for}156\mathrm{scouts}=156\times 15=2340 \\ \left(\mathrm{i}\right)\mathrm{When}39\mathrm{more}\mathrm{scouts}\mathrm{are}\mathrm{added},\mathrm{then}\mathrm{number}\mathrm{of}\mathrm{scouts}=156+39=195 \\ \mathrm{So},\mathrm{number}\mathrm{of}\mathrm{days}\mathrm{the}\mathrm{food}\mathrm{will}\mathrm{last}=\frac{2340}{195}=12 \\ \left(\mathrm{ii}\right)\mathrm{When}\mathrm{number}\mathrm{of}\mathrm{days}=26 \\ \mathrm{Then},\mathrm{number}\mathrm{of}\mathrm{scouts}=\frac{2340}{26}=90 \\ \mathrm{This}\mathrm{means}\mathrm{there}\mathrm{is}\mathrm{enough}\mathrm{food}\mathrm{for}90\mathrm{scouts}\mathrm{for}26\mathrm{days}. \\ \mathrm{Therefore},\mathrm{number}\mathrm{of}\mathrm{scouts}\mathrm{should}\mathrm{go}=156-90=66 \end{gathered}$$
Regards