Question

Any object of weight 500 kg wt is lifted by using a hydraulic press. The radii of the cross sections of the pump piston and the press piston are 10 cm and 20 cm respectively. Calculate the effort required to lift the object. Calculate the displacement of the load if the effort is moved through a distance of 20 cm.

Answer 1

$$\begin{gathered} Lettheeffortappliedisfonthecrossectionofradius0.1m. \\ SopressureP=f/\pi {\left(0.1\right)}^2. \\ AccordingtoPascal\text{'}slawofpressure,samepressureistransmittedinalldirection,so \\ Loadtobepickedup=P\times A \\ or500\times 10=\frac{f}{\pi {\left(o.1\right)}^2}\times \pi {\left(0.2\right)}^2=4f \\ orf=\frac{5000}{4}=1250N. \\ Nowtheamountofworkdonetodisplacethisload, \\ workdonebyeffort=workdonebyload \\ f\times s=F\times S \\ or1250\times 0.2=5000\times S \\ orS=\frac{1250\times 0.2}{5000}=\frac{250}{5000}=\frac{1}{20}m=\frac{100}{20}=5cm. \\ Sodisplacementofloadisby5cm. \end{gathered}$$