Question

In a new scale of temperature the lower fixed point is marked as 0 corresponding to the melting point of a substance which is equal to 25^oC and the upper fixed point is marked corresponding to the boiling point of the substance which is equal to 175^oC. The total length of the scale between the UFP and LFP is divided into 200 parts. Determine the temperature in the new scale when the temperature of a substance measured by a celcius thermometer is 50^oC.

Answer 1

$$\begin{gathered} AstheLFPandUFParefixedto25°cand175°c,so \\ \frac{t-25}{175-25}=\frac{50-0}{100-0},wheretisthetemperatureshownbythermometerinthenewscale. \\ So,\frac{t-25}{150}=\frac{1}{2} \\ ort-25=75 \\ ort=75+25=100°C \end{gathered}$$