Find the value of the following -i- tan2 10deg - cot2 80deg-ii- sec2 42deg - cosec2 48deg

1 #160;tan210 #176; cot280 #176;= #160;tan290 80 #176; cot280 #176;=cot280 #176; cot280 #176; #160; #160; #160; #160;Since #160;tan90 ...

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Graph of Trigonometric Ratios

Find the valu...

Question

Find the value of the following :-
(i) tan²10deg - cot2 80deg
(ii) sec2 42deg - cosec2 48deg

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(i) s e c^{2} θ + c o s e c^{2} θ = s e c^{2} θ c o s e c^{2} θ

(i i) t a n^{2} θ - s i n^{2} θ = t a n^{2} θ s i n^{2} θ

(i i i) t a n^{2} θ + c o t^{2} θ + 2 = s e c^{2} θ c o s e c^{2} θ

\frac{{c o s e c}^{2} 63^{0} + {t a n}^{2} 24^{0}}{{c o t}^{2} 66^{0} + {s e c}^{2} 27^{0}} + \frac{{s i n}^{2} 63^{0} + c o s 63^{0} {s i n 27}^{0} + {s i n 27}^{0} {s e c 63}^{0}}{2 ({c o s e c}^{2} 65^{0} - {t a n}^{2} 25^{0})}

{c o s e c}^{2} 51^{0} - {c o t}^{2} 51^{0}

6 {tan}^{2} θ + 54 {cot}^{2} θ + 18

I.

54

A . M . \geq G . M .

6 {tan}^{2} θ, 54 {cot}^{2} θ, 18

II.

54

A . M . \geq G . M .

6 {tan}^{2} θ, 54 {cot}^{2} θ; 18

III.

78

{tan}^{2} θ = {cot}^{2} θ

s e c^{2} 49^{\circ} - c o t^{2} 41^{\circ}

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