square root of 115+ square root of 41- square root of 21+ square root of 19 - square root of 9

Open in App

Solution

Dear student,

$\sqrt{115 + \sqrt{41 - \sqrt{21 + \sqrt{19 - \sqrt{9}}}}} = \sqrt{115 + \sqrt{41 - \sqrt{21 + \sqrt{19 - 3}}}} = \sqrt{115 + \sqrt{41 - \sqrt{21 + \sqrt{16}}}} = \sqrt{115 + \sqrt{41 - \sqrt{21 + 4}}} = \sqrt{115 + \sqrt{41 - \sqrt{25}}} = \sqrt{115 + \sqrt{41 - 5}} = \sqrt{115 + \sqrt{36}} = \sqrt{115 + 6} = \sqrt{121} = 11$

Regards

Suggest Corrections

Similar questions

Find the value of a in 3 - square root 5 / 3 + 2 square root 5 = a square root 5 - 19/11

The rationalising factor of 4 square root 5 .

Option

A. Square root 5

B. 3 square root 5

C. 4 square root 125

7

9

If square root of 5=2.236 and square root of 10=3.162 then what is the value of square root of 10 minus square root of 5 diveded by square root of 2.

Join BYJU'S Learning Program