TWO SOLDERING IRON ARE WORKING IN 250V.THE RESISTANCE OF ONE IS 500OHM AND THAT OF ANOTHER IS 750 OHM.AMONG THESE WHICH ONE HAS LARGER INTENSITY OF CURRENT?WHICH SOLDERING IRON HAS MORE POWER ?CALCULATE THE ENERGY CONSUMED IN UNITS WHEN A SOLDERING IRON OF 500 OHM WORKS FOR 2 HOURS?CALCULATE HEAT PRODUCED IN 5 MINUTES BY THE SOLDERING IRON HAVING THE RESISTANCE 750 OHM?

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$I n t e n s i t y o f c u r r e n t w i l l b e h i g h e r i n t h e 500 o h m a n d p o w e r o f 500 o h m s o l d e r i n g i r o n m o r e t h a n 750 o h m s o l d e r i n g i r o n . T h e e n e r g y c o n s u m e d b y 500 o h m s o l d e r i n g i r o n w o r k i n g f o r 2 h o u r s = \frac{V^{2}}{R} \times t = \frac{250 \times 250 \times 2}{500} = 250 W h = 0.25 K W h = 0.25 U . T h e e n e r g y c o n s u m e d b y 750 o h m s o l d e r i n g i r o n w o r k i n g f o r 5 m i n u t s o r \frac{5}{60} h = \frac{V^{2}}{R} \times t = \frac{250 \times 250 \times 5}{750 \times 60} = \frac{125}{' 18} ≃ 7 W h = 0.007 K W h = 0.007 U .$

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