Question

Simplify
3 x square root of 40 - 4 x cube root of 320 - cube root of 5

Answer 1

$$\begin{gathered} \mathrm{Hi}, \\ 3\times \sqrt{40}-4\sqrt[3]{320}-\sqrt[3]{5} \\ =3\times \sqrt{2\times 2\times 2\times 5}-4\sqrt[3]{2\times 2\times 2\times 2\times 2\times 2\times 5}-\sqrt[3]{5} \\ =3\times 2\sqrt{10}-4\times 2\times 2\times \sqrt[3]{5}-\sqrt[3]{5} \\ =6\sqrt{10}-16\sqrt[3]{5}-\sqrt[3]{5} \\ =6\sqrt{10}-17\sqrt[3]{5} \end{gathered}$$