Question

Solve this:
A force of 4.0 N acts on a body of mass 2.0 kg for 4.0 s. Assuming the body to be initially at rest, find
(a) its velocity when the force stops acting,
(b) the distance covered in 10 s after the force starts acting.

Answer 1

Dear Student ,
$$\begin{gathered} Accelerationofthebodyis,a=\frac{F}{m}=\frac{4}{2}=2m/s^2 \\ Sothevelocityaftertheforcestopsis, \\ v=u+at=0+\left(2\times 4\right)=8m/s \\ anddis\tan cecoveredin10s=s=ut+\frac{1}{2}a{t}^2=0+\frac{1}{2}\times 2\times 100=100m \end{gathered}$$
Regards