Let Q1 be heat entering the engine and Q2 and Q3 be the heat transfer to water.
To find: Heat transfer to the water Q2+Q3Q1
Given:
Efficiency η = 0.3
WP of pump = 5
We know,
Work, W = η Q1 = 0.3×Q1
Heat transferring to the water is given as
Q2 = (1-η) Q1 = 0.7Q1
Q3 = WP x W = 5 x 0.3 x Q1 = 1.5 Q1
Now,
Q2+Q3Q1 =0.7Q1+1.5Q1Q1=2.2Q1Q1=2.2
So we can say that
If the Q energy is taken by the heat engine the energy given to the water is 2.2 Q