Structural isomers possible for $C_{4} H_{8} B r_{2}$ are

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 9

There are $9$ structural isomers possible for this $C_{4} H_{8} B r_{2}$
Names:
$\to 1, 4 - d i b r o m o b u t a n e$
$\to 1, 3 - d i b r o m o b u t a n e$ (+ R/S)
$\to 1, 3 - d i b r o m o - 2 - m e t h y l p r o p a n e$
$\to 1, 2 - d i b r o m o b u t a n e$ (+ R/S)
$\to 1, 2 - d i b r o m o - 2 - m e t h y l p r o p a n e$
$\to 2, 3 - d i b r o m o b u t a n e$ (+ R/S)
$\to 1, 1 - d i b r o m o b u t a n e$
$\to 2, 2 - d i b r o m o b u t a n e$
$\to 1, 1 - d i b r o m o - 2 - m e t h y l p r o p a n e$
The $2, 3 - d i b r o m o b u t a n e$ would have free bond rotation about the $C_{2} - C_{3}$ bond, which is indicated with the "resonance" double arrow.
Option B is correct

Option B is correct.

Suggest Corrections

Similar questions

C_{4} H_{8} B r_{2}

C_{2} H_{4} B r_{2}

C_{4} H_{10} O

C_{7} H_{16}

Join BYJU'S Learning Program