The correct option is D ‘a′ carbon of glucose and ‘b′ carbon of fructose.
Anomeric carbon is at C−1 of a cyclic glucose and at C−2 of a cyclic fructose. It is adjacent to the oxygen atom of a cyclic structure in both the cases.
In the given structure of disaccharide, the anomeric carbon is “a” in case of glucose and it is “b” in case of fructose.
So, the correct answer is option (C).