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Question

# Structures of nuclei of three atoms A, B, and C are given below: A has 90 protons and 146 neutrons. B has 92 protons and 146 neutrons. C has 90 protons and 148 neutrons. Based on the above data, which of these atoms are isotopes and which are isobars?

A

A and C are isotopes; B and C are isobars

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B

A and B are isotopes; A and C are isobars

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C

B and C are isobars; A and B are isotopes

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D

A and C are isotopes; A and B are isobars

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Solution

## The correct option is A A and C are isotopes; B and C are isobars The mass number of A = number of protons + number of neutrons in A = 90+146=236 The mass number of B= number of protons + number of neutrons in B = 92+146 =238 The mass number of C= number of protons + number of neutrons in C = 90+148=238 So, A,B and C can be represented as: 23690A,23892B,23890C 23690A and 23890C are isotopes as they have same atomic number but different atomic mass/mass number 23892B,23890C are isobars as they have same atomic mass/mass number but different atomic numbers.

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