Students should take examples of their own and practise construction of triangles.

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Solution

In ∆PQR, l(PR) = 8 cm, m ∠PQR = 90^° , l(QR) = 6 cm.
Steps of construction
1. Draw a line QR = 6 cm.
2. With Q as centre, draw ∠XQR = 90º.
3. With R as centre and 8 cm as radius, cut an arc on XQ and name it as point P.
4. Join PR.
∆PQR is thus formed.

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Students should take examples of their own and practise construction of triangles.

In ∆PQR, l(PR) = 8 cm, m ∠PQR = 90° , l(QR) = 6 cm. Steps of construction 1. Draw a line QR = 6 cm. 2. With Q as centre, draw ∠XQR = 90º. 3. With R as centre and 8 cm as radius, cut an arc on XQ and name it as point P. 4. Join PR. ∆PQR is thus formed.

In ∆PQR, l(PR) = 8 cm, m ∠PQR = 90^° , l(QR) = 6 cm.
Steps of construction
1. Draw a line QR = 6 cm.
2. With Q as centre, draw ∠XQR = 90º.
3. With R as centre and 8 cm as radius, cut an arc on XQ and name it as point P.
4. Join PR.
∆PQR is thus formed.