Studies on the elevation in boiling point of $C a (N O_{3})_{2}$ gives its molar mass to be $131.2 g/mol$ . The degree of dissociation of $C a (N O_{3})_{2}$ is:

100 %

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75 %

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50 %

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12.5 %

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Solution

The correct option is D $12.5 %$
$C a (N O_{3})_{2} \to C a^{2 +} + 2 N O_{3}^{-} I n i t i a l 100 A t . e q 1 - α α 2 α$
As we know, $i = 1 + 2 α$
Calculated molecular weight of $C a (N O_{3})_{2} = 164 g / m o l$
Observed Molecular weight of $C a (N O_{3})_{2} = 131.2 g / m o l$
$i = \frac{164}{131.2} = 1 + 2 α$
$∴ α = 0.125 = 12.5 %$

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Similar questions

C a {(N O_{3})}_{2}

C a {(N O_{3})}_{2}

C a (N O_{3})_{2}

131.2 g/mol

C a (N O_{3})_{2}

X Y_{2}

Normal molar mass = 164 g / m o l

65.6 g / m o l

X Y_{2}

65.6

X Y_{2}

164

65.6

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