    Question

# Study the following circuit diagram in figure and mark the correct option (s). A
The potential of point 'a' with respect to point 'b' when switch S is open is 6 V.
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B
The points 'a' and 'b', are the same potential, when S is opened.
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C
The charge that flows through switch S, when it is closed is 54 μC.
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D
The final potential of 'b' with respect to ground when switch S is closed is 8 V.
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Solution

## The correct options are A The potential of point 'a' with respect to point 'b' when switch S is open is −6 V. C The charge that flows through switch S, when it is closed is 54 μC.When S is opened: Vc−Va=18×66+3=12 V⇒Va=6 V The two capacitors are in series: Ceq=2 μF q=CV=18×2=36 μC ⇒Vc−Vb=366=6 V ⇒Vb=12 V ⇒Va−Vb=−6 V After S is closed: The potential difference across 6 Ω resistor will be same as 6 μF capacitor. Final potential of 'b' is 6 V. ∴q′1=CV=6×12=72 μC and q′2=CV=3×6=18 μC Charges flown after S is closed: q1=72−36=36 μC,q2=36−18=18 μC Charges flown through S after it is closed : 36+18=54μC  Suggest Corrections  0      Similar questions
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