Question

Study the following diagram.
Is sum of the number of people in only B and the number of people common in both A and B is $63$ and the number of people in B is twice the number of people in A, then the values of x and y are respectively.

• A. $15,4$
• B. $48,5$
• C. $51,7$
• D. $51,8$

Answer 1

The correct option is C $51,7$

People only in B $=x$

People common to A and B $=(y+5)$

$x+y+5=63$

$x+y=58$ --------------(1)

Total number of people in B $=$ $(x+y+11+5)=x+y+16$

Total number of people in A $=$ $(15+5+10+y)=30+y$

$x+y+16$$=2$$(30+y)$

$x+y+16=60+2y$

$x-y=44$ ------------(2)

Solving I and 2, we get

$x=51$

$y=7$

Hence, Option C is correct.