wiz-icon
MyQuestionIcon
MyQuestionIcon
12
You visited us 12 times! Enjoying our articles? Unlock Full Access!
Question

Study the following vt graphs in Column I carefully and match appropriately with the statements given in Column II. Assume that motion takes place from time 0 to T.

A
i(q),(s);ii(p),(s);iii(r);iv(p)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
i(q),(s);ii(p);iii(r),(s);iv(p),(s)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
i(p),(s);ii(q),(s);iii(r);iv(p),(q)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
i(p),(s);ii(q);iii(r),(s);iv(q)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A i(q),(s);ii(p),(s);iii(r);iv(p)
i. Area of vt graph lies below time axis, so displacement is negative. But slope is positive, so acceleration is positive.
ii. Area of vt graph lies above time axis, so displacement is positive. And slope is positive, so acceleration is also positive.
iii. Displacement is zero, because half area is above time axis and half below. Slope is negative, so acceleration is negative.
iv. Area of vt graph lies above time axis, so displacement is positive. And slope is negative, so acceleration is negative.

flag
Suggest Corrections
thumbs-up
4
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Acceleration
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon