Question

Study the given figures representing the process of binary fission in Amoeba. Arrange the figures in the correct sequence and select the correct answer.

• A. $\left(iv\right)\to \left(iii\right)\to \left(i\right)\to \left(ii\right)\to \left(v\right)$
• B. $\left(iii\right)\to \left(iv\right)\to \left(i\right)\to \left(ii\right)\to \left(v\right)$
• C. $\left(iii\right)\to \left(v\right)\to \left(ii\right)\to \left(iv\right)\to \left(i\right)$
• D. $\left(iv\right)\to \left(iii\right)\to \left(ii\right)\to \left(v\right)\to \left(i\right)$

Answer 1

The correct option is C $\left(iii\right)\to \left(v\right)\to \left(ii\right)\to \left(iv\right)\to \left(i\right)$

In Amoeba, irregular binary fission occurs. The plane of division of cytoplasm is variable but is always at right angles to the elongated dividing nucleus. In this, the replicated chromosomes are separated by intranuclear mitosis and the nucleus divides by furrowing. Then the cytoplasm gradually constricts between the two separating nuclei, ultimately forming two equal-sized daughter individuals, each with a nucleus. The offspring grow to the size of the parent before dividing again.

So, the correct answer is (iii)→(v)→(ii)→(iv)→(i).