Study the pattern and write next step:
$8789 - 9 = 8789 - (10 - 1) = 8780$
$8789 - 99 = 8789 - (100 - 1) = 8690$
$8789 - 999 = 8789 - (1000 - 1) = - 1210$

8789 - 999 = 8789 - (1000 - 1) = 6778

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8789 - 999 = 8789 - (1000 - 1) = 7768

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8789 - 999 = 8789 - (1000 - 1) = 8678

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8789 - 999 = 8789 - (10000 - 1) = - 1210

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Solution

The correct option is D $8789 - 999 = 8789 - (10000 - 1) = - 1210$
$N o w 8789 - 9 = 8789 - (10 - 1) = 8780 8789 - 99 = 8789 - (100 - 1) = 8690 8789 - 999 = 8789 - (1000 - 1) = 7790 8789 - 9999 = 8789 - (10000 - 1) = - 1210$

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Similar questions

85 \times (9) = 85 \times (10 - 1) = 765

85 \times (99) = 85 \times (100 - 1) = 8, 415

85 \times (999) = 85 \times (1000 - 1) = 84, 915

[\frac{1}{2}] + [\frac{1}{2} + \frac{1}{1000}] + [\frac{1}{2} + \frac{2}{1000}] + [\frac{1}{2} + \frac{3}{1000}] + . . . + [\frac{1}{2} + \frac{999}{1000}] = 500

[\frac{1}{2} + \frac{r}{1000}] = {\begin{matrix} 0; & if 0 \leq r < 500 1; & if 500 \leq r \leq 999 \end{matrix}

1000 [\frac{1}{1 \times 2} + \frac{1}{2 \times 3} + \frac{1}{3 \times 4} + . . . . . \frac{1}{999 \times 1000}]

[x]

[\frac{1}{2} + \frac{1}{1000}] + [\frac{1}{2} + \frac{2}{1000}] + \dots . + [\frac{1}{2} + \frac{999}{1000}] =

1000 [\frac{1}{1 \times 2} + \frac{1}{2 \times 3} + \frac{1}{3 \times 4} + . . . + \frac{1}{999 \times 1000}]

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