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Ions

Study the rea...

Question

Study the reaction given below and write the electronic configuration of $C l^{-}$ when Cl is 2, 8, 7.

$C l + e^{-} \to C l^{-}$

2, 8, 7

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2, 8, 8

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2, 8, 1

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2, 8, 6

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Solution

The correct option is B
2, 8, 8

In the given reaction chlorine gains an electron to form an ion. This ion is negatively charged and is called the anion.

$C l + e^{-} \to C l^{-}$

The electronic configuration of $C l^{-}$ is 2, 8, 8 (configuration of Argon) as it receives one electron.

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Similar questions

N a + C l \to N a^{+} + C l^{-} \to N a^{+} C l^{-}

N a

C l

N a^{+}

C l^{-}

C l^{-}

N a^{+}

C l^{-}

N a^{+}

Which inert gas electron configuration do the Cl atoms in $C l_{2}$ molecule resemble? What is the electron configuration?

Identify the correct reaction from the options given below for the electrolysis of $C u C l_{2}$ .

\begin{matrix} N a^{+} & C l^{-} & N a^{+} & C l^{-} & N a^{+} & C l^{-} C l^{-} & □ & C l^{-} & N a^{+} & □ & N a^{+} N a^{+} & C l^{-} & □ & N a^{+} & C l^{-} & C l^{-} C l^{-} & N a^{+} & C l^{-} & N a^{+} & □ & N a^{+} \end{matrix}

N a \to N a^{+} + e^{-}

C l + e^{-} \to C l^{-}

C l^{-}

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