Study the table carefully to answer the questions that follow-Table shows the number of Students in thousands passed in an examination held in five different Universities in six yearsYear-A-B-C-D-EWhline2005-12-4imid 8-3 - 14-3imid 8-4-4-3-mid 3-4-4-72007-13-7 7-8 - 7-6imid 4-8-5-8imid 6-8-9-36-3 - 8-4imid 3-2Whline 2008-18-4imid 9-9 - 10-4imid 8-4-7-4 array What is the percentage decrease in the number of boys who passed in the exam from University -D in the year 2009 in comparison to the previous year -

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Question

Study the table carefully to answer the questions that follow:

Table shows the number of Students (in thousands) passed in an examination held in five different Universities in six years

$\begin{matrix} Y e a r & A & B & C & D & E B o y s ∣ G i r l s & B o y s ∣ G i r l s & B o y s ∣ G i r l s & B o y s ∣ G i r l s & B o y s ∣ G i r l s 2005 & 12.4 ∣ 8.3 & 14.3 ∣ 8.4 & 4.3 ∣ 3.4 & 4.7 ∣ 2.1 & 9.8 ∣ 3.1 2006 & 11.6 ∣ 6.4 & 8.9 ∣ 7.2 & 4.9 ∣ 4.3 & 5.8 ∣ 4.3 & 7.3 ∣ 4.3 2007 & 13.7 ∣ 7.8 & 7.6 ∣ 4.8 & 5.8 ∣ 6.8 & 9.3 ∣ 6.3 & 8.4 ∣ 3.2 2008 & 18.4 ∣ 9.9 & 10.4 ∣ 8.4 & 7.4 ∣ 7.2 & 9.6 ∣ 4.4 & 4.6 ∣ 4.2 2009 & 14.8 ∣ 11.4 & 9.6 ∣ 7.2 & 8.9 ∣ 6.1 & 8.4 ∣ 5.2 & 6.8 ∣ 3.1 2010 & 18.2 ∣ 16.2 & 7.4 ∣ 5.2 & 11.8 ∣ 9.3 & 7.3 ∣ 5.1 & 7.8 ∣ 6.3 \end{matrix}$

What is the percentage decrease in the number of boys who passed in the exam from University – D in the year 2009 in comparison to the previous year ?

12.5

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3.8

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7.5

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15.8

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None of these

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Solution

The correct option is A
12.5

Decrease in the number of boys who pass
= (9.6 – 8.4) thousand
= 1.2 thousand
$∴$ Required percentage decrease $= \frac{1.2}{9.6} \times 100$ = 12.5

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Similar questions

Study the table carefully to answer the questions that follow:

Table shows the number of Students (in thousands) passed in an examination held in five different Universities in six years

$\begin{matrix} Y e a r & A & B & C & D & E B o y s ∣ G i r l s & B o y s ∣ G i r l s & B o y s ∣ G i r l s & B o y s ∣ G i r l s & B o y s ∣ G i r l s 2005 & 12.4 ∣ 8.3 & 14.3 ∣ 8.4 & 4.3 ∣ 3.4 & 4.7 ∣ 2.1 & 9.8 ∣ 3.1 2006 & 11.6 ∣ 6.4 & 8.9 ∣ 7.2 & 4.9 ∣ 4.3 & 5.8 ∣ 4.3 & 7.3 ∣ 4.3 2007 & 13.7 ∣ 7.8 & 7.6 ∣ 4.8 & 5.8 ∣ 6.8 & 9.3 ∣ 6.3 & 8.4 ∣ 3.2 2008 & 18.4 ∣ 9.9 & 10.4 ∣ 8.4 & 7.4 ∣ 7.2 & 9.6 ∣ 4.4 & 4.6 ∣ 4.2 2009 & 14.8 ∣ 11.4 & 9.6 ∣ 7.2 & 8.9 ∣ 6.1 & 8.4 ∣ 5.2 & 6.8 ∣ 3.1 2010 & 18.2 ∣ 16.2 & 7.4 ∣ 5.2 & 11.8 ∣ 9.3 & 7.3 ∣ 5.1 & 7.8 ∣ 6.3 \end{matrix}$

From which University and in which year respectively was the number of girls who passed in the exam more than the number of boys who passed in the exam ?

Study the table carefully to answer the questions that follow:

Table shows the number of Students (in thousands) passed in an examination held in five different Universities in six years

Twenty percent of the total students who passed in the exams from all the Universities together in the year 2009 got distinction.
What was the number of such students who got distinction?

Study the table carefully to answer the questions that follow:

Table shows the number of Students (in thousands) passed in an examination held in five different Universities in six years

Number of girls who passed in the exam from University – B in the year 2006 was approximately what percentage of the number of boys who passed in the exam from University – A in the year 2010 ?

Study the table carefully to answer the questions that follow:

Table shows the number of Students (in thousands) passed in an examination held in five different Universities in six years

What was the approximate average number of girls who passed in the exam from University E over all the years together ?

Q. What is the percentage decrease in the number of boys who passed in the exam from university D in the year 2009 in comparison to the previous year?

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The correct option is A 12.5 Decrease in the number of boys who pass = (9.6 – 8.4) thousand = 1.2 thousand ∴ Required percentage decrease =1.29.6×100 = 12.5

The correct option is A
12.5

Decrease in the number of boys who pass
= (9.6 – 8.4) thousand
= 1.2 thousand
$∴$ Required percentage decrease $= \frac{1.2}{9.6} \times 100$ = 12.5