Study the table carefully to answer the questions that follow-Table shows the number of Students in thousands passed in an examination held in five different Universities in six yearsYear-A-B-C-D-EWhline2005-12-4imid 8-3 - 14-3imid 8-4-4-3-mid 3-4-4-72007-13-7 7-8 - 7-6imid 4-8-5-8imid 6-8-9-36-3 - 8-4imid 3-2Whline array Twenty percent of the total students who passed in the exams from all the Universities together in the year 2009 got distinction- What was the number of such students who got distinction-

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Mean for Ungrouped Data

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Question

Study the table carefully to answer the questions that follow:

Table shows the number of Students (in thousands) passed in an examination held in five different Universities in six years

$\begin{matrix} Y e a r & A & B & C & D & E B o y s ∣ G i r l s & B o y s ∣ G i r l s & B o y s ∣ G i r l s & B o y s ∣ G i r l s & B o y s ∣ G i r l s 2005 & 12.4 ∣ 8.3 & 14.3 ∣ 8.4 & 4.3 ∣ 3.4 & 4.7 ∣ 2.1 & 9.8 ∣ 3.1 2006 & 11.6 ∣ 6.4 & 8.9 ∣ 7.2 & 4.9 ∣ 4.3 & 5.8 ∣ 4.3 & 7.3 ∣ 4.3 2007 & 13.7 ∣ 7.8 & 7.6 ∣ 4.8 & 5.8 ∣ 6.8 & 9.3 ∣ 6.3 & 8.4 ∣ 3.2 2008 & 18.4 ∣ 9.9 & 10.4 ∣ 8.4 & 7.4 ∣ 7.2 & 9.6 ∣ 4.4 & 4.6 ∣ 4.2 2009 & 14.8 ∣ 11.4 & 9.6 ∣ 7.2 & 8.9 ∣ 6.1 & 8.4 ∣ 5.2 & 6.8 ∣ 3.1 2010 & 18.2 ∣ 16.2 & 7.4 ∣ 5.2 & 11.8 ∣ 9.3 & 7.3 ∣ 5.1 & 7.8 ∣ 6.3 \end{matrix}$

Twenty percent of the total students who passed in the exams from all the Universities together in the year 2009 got distinction.
What was the number of such students who got distinction?

17,600

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16,300

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18,600

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81,500

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None of these

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Solution

The correct option is B
16,300

Total students who passed from all the universities together in the year 2009 = 81.5 thousand
$∴$ Number of students who got distinction
$= (\frac{81.5 \times 20}{100})$ thousand
= 16300

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Similar questions

Study the table carefully to answer the questions that follow:

Table shows the number of Students (in thousands) passed in an examination held in five different Universities in six years

$\begin{matrix} Y e a r & A & B & C & D & E B o y s ∣ G i r l s & B o y s ∣ G i r l s & B o y s ∣ G i r l s & B o y s ∣ G i r l s & B o y s ∣ G i r l s 2005 & 12.4 ∣ 8.3 & 14.3 ∣ 8.4 & 4.3 ∣ 3.4 & 4.7 ∣ 2.1 & 9.8 ∣ 3.1 2006 & 11.6 ∣ 6.4 & 8.9 ∣ 7.2 & 4.9 ∣ 4.3 & 5.8 ∣ 4.3 & 7.3 ∣ 4.3 2007 & 13.7 ∣ 7.8 & 7.6 ∣ 4.8 & 5.8 ∣ 6.8 & 9.3 ∣ 6.3 & 8.4 ∣ 3.2 2008 & 18.4 ∣ 9.9 & 10.4 ∣ 8.4 & 7.4 ∣ 7.2 & 9.6 ∣ 4.4 & 4.6 ∣ 4.2 2009 & 14.8 ∣ 11.4 & 9.6 ∣ 7.2 & 8.9 ∣ 6.1 & 8.4 ∣ 5.2 & 6.8 ∣ 3.1 2010 & 18.2 ∣ 16.2 & 7.4 ∣ 5.2 & 11.8 ∣ 9.3 & 7.3 ∣ 5.1 & 7.8 ∣ 6.3 \end{matrix}$

From which University and in which year respectively was the number of girls who passed in the exam more than the number of boys who passed in the exam ?

Study the table carefully to answer the questions that follow:

Table shows the number of Students (in thousands) passed in an examination held in five different Universities in six years

What is the percentage decrease in the number of boys who passed in the exam from University – D in the year 2009 in comparison to the previous year ?

Study the table carefully to answer the questions that follow:

Table shows the number of Students (in thousands) passed in an examination held in five different Universities in six years

What was the approximate average number of girls who passed in the exam from University E over all the years together ?

Q. Twenty percent of the total students, who passed the exam from all the universities together in the year 2009 got a distinction. What was the total number of such students who got the distinction?

Study the table carefully to answer the questions that follow:

Table shows the number of Students (in thousands) passed in an examination held in five different Universities in six years

Number of girls who passed in the exam from University – B in the year 2006 was approximately what percentage of the number of boys who passed in the exam from University – A in the year 2010 ?

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The correct option is B 16,300 Total students who passed from all the universities together in the year 2009 = 81.5 thousand ∴ Number of students who got distinction =(81.5×20100) thousand = 16300

The correct option is B
16,300

Total students who passed from all the universities together in the year 2009 = 81.5 thousand
$∴$ Number of students who got distinction
$= (\frac{81.5 \times 20}{100})$ thousand
= 16300