Study the table carefully to answer the questions that follow-Table shows the number of Students in thousands passed in an examination held in five different Universities in six yearsYear-A-B-C-D-Elllhline2009-14-8 1 -mid 11-4array What was the approximate average number of girls who passed in the exam from University E over all the years together-A- 4030B- 4080C- 4000D- 3030E- 3080

The correct option is A 4030 Average number of girls who passed from university E = (3.1+4.3+3.2+4.2+3.1+6.3 )/6× 1000 = 24.2×1000/6≈ 4030 ...

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Standard XII

Mathematics

Range

Study the tab...

Question

Study the table carefully to answer the questions that follow:

Table shows the number of Students (in thousands) passed in an examination held in five different Universities in six years

$\begin{matrix} Y e a r & A & B & C & D & E B o y s ∣ G i r l s & B o y s ∣ G i r l s & B o y s ∣ G i r l s & B o y s ∣ G i r l s & B o y s ∣ G i r l s 2005 & 12.4 ∣ 8.3 & 14.3 ∣ 8.4 & 4.3 ∣ 3.4 & 4.7 ∣ 2.1 & 9.8 ∣ 3.1 2006 & 11.6 ∣ 6.4 & 8.9 ∣ 7.2 & 4.9 ∣ 4.3 & 5.8 ∣ 4.3 & 7.3 ∣ 4.3 2007 & 13.7 ∣ 7.8 & 7.6 ∣ 4.8 & 5.8 ∣ 6.8 & 9.3 ∣ 6.3 & 8.4 ∣ 3.2 2008 & 18.4 ∣ 9.9 & 10.4 ∣ 8.4 & 7.4 ∣ 7.2 & 9.6 ∣ 4.4 & 4.6 ∣ 4.2 2009 & 14.8 ∣ 11.4 & 9.6 ∣ 7.2 & 8.9 ∣ 6.1 & 8.4 ∣ 5.2 & 6.8 ∣ 3.1 2010 & 18.2 ∣ 16.2 & 7.4 ∣ 5.2 & 11.8 ∣ 9.3 & 7.3 ∣ 5.1 & 7.8 ∣ 6.3 \end{matrix}$

What was the approximate average number of girls who passed in the exam from University E over all the years together ?

4030

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4080

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4000

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3030

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3080

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Solution

The correct option is A
4030

Average number of girls who passed from university E
$= \frac{(3.1 + 4.3 + 3.2 + 4.2 + 3.1 + 6.3)}{6} \times 1000$
$= \frac{24.2 \times 1000}{6} \approx 4030$

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Similar questions

Study the table carefully to answer the questions that follow:

Table shows the number of Students (in thousands) passed in an examination held in five different Universities in six years

$\begin{matrix} Y e a r & A & B & C & D & E B o y s ∣ G i r l s & B o y s ∣ G i r l s & B o y s ∣ G i r l s & B o y s ∣ G i r l s & B o y s ∣ G i r l s 2005 & 12.4 ∣ 8.3 & 14.3 ∣ 8.4 & 4.3 ∣ 3.4 & 4.7 ∣ 2.1 & 9.8 ∣ 3.1 2006 & 11.6 ∣ 6.4 & 8.9 ∣ 7.2 & 4.9 ∣ 4.3 & 5.8 ∣ 4.3 & 7.3 ∣ 4.3 2007 & 13.7 ∣ 7.8 & 7.6 ∣ 4.8 & 5.8 ∣ 6.8 & 9.3 ∣ 6.3 & 8.4 ∣ 3.2 2008 & 18.4 ∣ 9.9 & 10.4 ∣ 8.4 & 7.4 ∣ 7.2 & 9.6 ∣ 4.4 & 4.6 ∣ 4.2 2009 & 14.8 ∣ 11.4 & 9.6 ∣ 7.2 & 8.9 ∣ 6.1 & 8.4 ∣ 5.2 & 6.8 ∣ 3.1 2010 & 18.2 ∣ 16.2 & 7.4 ∣ 5.2 & 11.8 ∣ 9.3 & 7.3 ∣ 5.1 & 7.8 ∣ 6.3 \end{matrix}$

Number of girls who passed in the exam from University – B in the year 2006 was approximately what percentage of the number of boys who passed in the exam from University – A in the year 2010 ?

Study the table carefully to answer the questions that follow:

Table shows the number of Students (in thousands) passed in an examination held in five different Universities in six years

From which University and in which year respectively was the number of girls who passed in the exam more than the number of boys who passed in the exam ?

Study the table carefully to answer the questions that follow:

Table shows the number of Students (in thousands) passed in an examination held in five different Universities in six years

Twenty percent of the total students who passed in the exams from all the Universities together in the year 2009 got distinction.
What was the number of such students who got distinction?

Study the table carefully to answer the questions that follow:

Table shows the number of Students (in thousands) passed in an examination held in five different Universities in six years

What is the percentage decrease in the number of boys who passed in the exam from University – D in the year 2009 in comparison to the previous year ?

Q. What was the approximate average number of girls who passed in the exam from university E over all the years together?

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The correct option is A 4030 Average number of girls who passed from university E =(3.1+4.3+3.2+4.2+3.1+6.3)6×1000 =24.2×10006≈4030

The correct option is A
4030

Average number of girls who passed from university E
$= \frac{(3.1 + 4.3 + 3.2 + 4.2 + 3.1 + 6.3)}{6} \times 1000$
$= \frac{24.2 \times 1000}{6} \approx 4030$