Sub-normal to $x y = c^{2}$ at any point on it varies directly as

cube of ordinate

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square of ordinate

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ordinate

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cube of abscissa

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Solution

The correct option is A cube of ordinate
SN $=$ (ym)
$= (y \frac{d y}{d x})$
$= (y \times \frac{c^{2}}{- x^{2}})$
$= | \frac{y^{3} c^{2}}{c^{2}} |$
$= | \frac{c^{2}}{x^{3}} |$

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Similar questions

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x y = 54

x y = a^{2}

The sub-normal at any point of the curve $x^{2} y^{2} = a^{2} (x^{2} - a^{2})$ varies as

x^{2} y^{2} = a^{2} (x^{2} - a^{2})

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