Subhana started work in 1995at an annual salary of ₹5000and received an increment of₹200each year.in which year did his income reach₹7000
It can be observed that the incomes that Subba Rao obtained in various years are in A.P as every year, his salary is increased by Rs. 200.
Therefore, the salaries of each year after 1995 are;
5000, 5200, 5400, …
Here, a = 5000
d = 200
Let after nth year, his salary be Rs. 7000.
Therefore, an=a+(n−1)d
7000 = 5000 + (n − 1) 200
200(n − 1) = 2000
(n − 1) = 10
n = 11
Thus, 1995 + 10 = 2005
Hence, his salary reached at Rs. 7000 in 2005.