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Byju's Answer
Standard XII
Chemistry
Ostwald Dilution Law Mathematical Interpretation
Substance ka...
Question
Substance
k
a
Hydrogen carbonate ion (bicarbonate ion)
H
C
O
−
3
4.8
×
10
−
11
Hydrogen phosphate ion
H
P
O
−
3
4
3.6
×
10
−
13
Water
H
2
O
1.0
×
10
−
14
Hydrogen sulfide ion
H
S
−
1.0
×
10
−
19
Using acid dissociation constants above, which substance is the strongest base?
A
C
O
2
−
3
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B
P
O
3
−
4
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C
O
H
−
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D
S
2
−
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Solution
The correct option is
D
S
2
−
K
a
×
K
b
=
K
W
=
10
−
14
A strong base is one which has higher value of
K
b
.
Since product of
K
a
and
K
b
is constant, higher value of
K
b
corresponds to lower value of
K
a
.
Hence, a strong base has a lower value of
K
a
.
Also, weaker the acid, stronger is its conjugate base.
From the given data,
H
S
−
is the weakest acid having least value of
K
a
. Hence, its conjugate base
S
2
−
is the strongest.
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0
Similar questions
Q.
Assertion :A substance that can either act as an acid or a base is called ampholyte. Reason: Bisulphide ion
(
H
S
−
)
and bicarbonate ion
(
H
C
O
−
3
)
are ampholytes.
Q.
Determine the hydrogen ion concentration in
1.0
N
solution of
H
C
N
if its dissociation constant is
4.0
×
10
−
10
.
Q.
An aqueous solution contains
0.10
M
H
2
S
and
0.20
M
H
C
l
. If the equilibrium constants for the formation
H
S
−
from
H
2
S
is
1.0
×
10
−
7
and that of
S
2
−
from ions
H
S
−
is
1.2
×
10
−
13
then the concentration of
S
2
−
ions in aqueous solution is:
Q.
An aqueous solution contains 0.10 M
H
2
S
and 0.20 M
H
C
l
. If the equilibrium constants for the formation of
H
S
−
from
H
2
S
is
1.0
×
10
−
7
and that of
S
2
−
from
H
S
−
ions is
1.2
×
10
−
13
, then the concentration of
S
2
−
ions in aqueous solution is:
Q.
An aqueous solution
0.10
M
H
2
S
ans
0.20
M
H
C
l
. If the equilibrium constants for the formation of
H
S
−
from
H
2
S
is
1.0
×
10
−
7
and that of
S
2
−
from
H
S
−
ions is
1.2
×
10
−
13
then the concentration of
S
2
−
ions in aqueous solution is:
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