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Assigning Oxidation Numbers

Substances th...

Question

Substances that are oxidised and reduced in the following reaction are respectively,
$N_{2} H_{4} (l) + 2 H_{2} O_{2} (l) ⟶ N_{2} (g) + 4 H_{2} O (l)$

H_{2} O, N_{2}

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N_{2} H_{4}, H_{2} O

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N_{2}, H_{2} O_{2}

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N_{2} H_{4}, H_{2} O_{2}

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Solution

The correct option is D $N_{2} H_{4}, H_{2} O_{2}$

$N_{2} H_{4}$ and $H_{2} O_{2}$ are oxidised and reduced in the reaction respectively.

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Similar questions

N_{2} H_{4 (l)} + 2 H_{2} O_{2 (l)} \to N_{2 (g)} + 4 H_{2} O_{(l)}

Identify the substance oxidised, reduced, oxidising agent and reducing agent for each of the following reactions:

(a) 2AgBr (s) + C₆H₆O₂(aq) → 2Ag(s) + 2HBr (aq) + C₆H₄O₂(aq)

(b) HCHO(l) + 2[Ag (NH₃)₂]⁺(aq) + 3OH^–(aq) → 2Ag(s) + HCOO^–(aq) + 4NH₃(aq) + 2H₂O(l)

(d) N₂H₄(l) + 2H₂O₂(l) → N₂(g) + 4H₂O(l)

(e) Pb(s) + PbO₂(s) + 2H₂SO₄(aq) → 2PbSO₄(s) + 2H₂O(l)

H_{2} O_{2} (l),

N_{2} H_{4} (l) + 2 H_{2} O_{2} (l) \to N_{2} (g) + 4 H_{2} O (l);

△_{r} H_{1}^{o} = - 818 k J / m o l

N_{2} H_{4} (l) + O_{2} (g) \to N_{2} (g) + 2 H_{2} O (l);

△_{r} H_{2}^{o} = - 622 k J / m o l

H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l); △_{f} H_{3}^{o} = - 285 k J / m o l

Identify the substances that are oxidised and the substances that are reduced in the following reactions.

(i)

(ii)

2 H_{2} S_{(g)} + S O_{2 (g)} \to 3 S_{(s)} + 2 H_{2} O_{(1)}

C u O_{(s)} + H_{2 (g)} \to C u_{(s)} + H_{2} O

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