Substituting $x = - 3$ in
$x^{2} - 5 x + 4$

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Solution

The correct option is B $28$
For $x = - 3$
$x^{2} - 5 x + 4$
$= (- 3)^{2} - 5 (- 3) + 4$
$= 9 + 15 + 4$
$= 28 \neq R . H . S$
The correct statement is $x^{2} + 5 x + 4 = 28$

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Similar questions

Substituting $x = - 3$ in $x^{2} + 5 x$ gives $3^{2} + 5 (- 3) = - 9 - 15 = - 24.$

Q. Find and correct error in the following mathematical statement.
Substituting

x = - 3

in:
(a)

x^{2} + 5 x + 4

gives

(- 3)^{2} + 5 (- 3) + 4 = 9 + 2 + 4 = 15

(b)

x^{2} - 5 x + 4

gives

(- 3)^{2} - 5 (- 3) + 4 = 9 - 15 + 4 = - 2

(c)

x^{2} + 5 x

gives

(- 3)^{2} + 5 (- 3) = - 9 - 15 = - 24

Find and correct the errors in the following mathematical statement. Substituting x = −3 in

(a) x² + 5x + 4 gives (−3)² + 5 (−3) + 4 = 9 + 2 + 4 = 15

(b) x² − 5x + 4 gives (−3)² − 5 (−3) + 4 = 9 − 15 + 4 = −2

Find and correct the errors in the following mathematical statement, Substituting $x = - 3$ in
$x^{2} + 5 x + 4$ gives $(- 3)^{2} + 5 (- 3) + 4 = 9 + 2 + 4 = 15$

Question 10(ii)
Find and correct the errors in the following mathematical statement. Substituting $x = - 3$ in
$x^{2} - 5 x + 4 g i v e s (- 3)^{2} - 5 (- 3) = 9 - 15 + 4 = - 2$

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Substituting x=−3 inx2−5x+4

The correct option is B 28For x=−3 x2−5x+4=(−3)2−5(−3)+4=9+15+4=28≠R.H.SThe correct statement is x2+5x+4=28

Substituting $x = - 3$ in
$x^{2} - 5 x + 4$

The correct option is B $28$
For $x = - 3$
$x^{2} - 5 x + 4$
$= (- 3)^{2} - 5 (- 3) + 4$
$= 9 + 15 + 4$
$= 28 \neq R . H . S$
The correct statement is $x^{2} + 5 x + 4 = 28$