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Factors of algebraic expressions and factorisation

Substituting ...

Question

Substituting $x = - 3$ in $(x^{2}) - 5 x$ gives
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Solution

Substituting $x = - 3$ in $(x^{2}) - 5 x$ gives $(- 3)^{2} - 5 (- 3) = 9 + 15 = 24$
Here $(- 3)^{2} = 9$ ,not -9.

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Substituting $x = - 3$ in $(x^{2}) - 5 x$ gives

Substituting $x = - 3$ in $x^{2} + 5 x$ gives $3^{2} + 5 (- 3) = - 9 - 15 = - 24.$

Q. Substituting

x = - 3

x^{2} + 5 x + 4

Find and correct the errors in the following mathematical statement. Substituting x = −3 in

(a) x² + 5x + 4 gives (−3)² + 5 (−3) + 4 = 9 + 2 + 4 = 15

(b) x² − 5x + 4 gives (−3)² − 5 (−3) + 4 = 9 − 15 + 4 = −2

(c) x² + 5x gives (−3)² + 5 (−3) = −9 − 15 = −24

Q. Find and correct error in the following mathematical statement.
Substituting

x = - 3

x^{2} + 5 x + 4

(- 3)^{2} + 5 (- 3) + 4 = 9 + 2 + 4 = 15

x^{2} - 5 x + 4

(- 3)^{2} - 5 (- 3) + 4 = 9 - 15 + 4 = - 2

x^{2} + 5 x

(- 3)^{2} + 5 (- 3) = - 9 - 15 = - 24

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