Subtract:

(1) $4 x^{2}$ and $- 6 x y^{2}$

(2) $6 x^{3}$ and $- 2 x^{3}$

(3) $9 x y a n d 5 x y$

(4) $- 7 x^{3}$ and $- 8 x^{3} y$

(1)

4 x^{2} + 6 x y^{2}

(2)

8 x^{3}

(3) 4xy
(4)

- 7 x^{3} + 8 x^{3} y

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(1)

4 x^{2} y - 6 x y^{2}

(2)

4 x^{3}

(3) -4xy
(4)

- 7 x^{3} - 8 x^{3} y

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(1)

10 x^{2} y

(2)

4 x^{3}

(3) 4xy
(4)

- 7 x^{3} + 8 x^{3} y

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none

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Solution

The correct option is
A

(1) $4 x^{2} + 6 x y^{2}$

(2) $8 x^{3}$

(3) 4xy

(4) $- 7 x^{3} + 8 x^{3} y$

Given,

(1) $4 x^{2} a n d - 6 x y^{2}$
(2) $6 x^{3} a n d - 2 x^{3}$
(3) $9 x y a n d 5 x y$
(4) $- 7 x^{3} a n d - 8 x^{3} y$

(1) $4 x^{2} a n d - 6 x y^{2}$

$= 4 x^{2} - (- 6 x y^{2})$

$= 4 x^{2} + 6 x y^{2}$

(2) $6 x^{3} a n d - 2 x^{3}$

$= 6 x^{3} - (- 2 x^{3})$

$= 6 x^{3} + 2 x^{3}$

$= 8 x^{3}$

(3) $9 x y a n d 5 x y$

$= 9 x y - 5 x y$

$= 4 x y$

(4) $- 7 x^{3} a n d - 8 x^{3} y$

$= - 7 x^{3} - (- 8 x^{3} y)$

$= - 7 x^{3} + 8 x^{3} y$

Suggest Corrections

Similar questions

What must be subtracted from $(4 x^{3} - 3 x + 5)$ to get $(2 x^{2} - 3 x^{3} + 5 x - 2)$ ?

4 x^{3} - 3 x + 5

2 x^{2} - 3 x^{3} + 5 x - 2

4 x^{2} - 7 x^{3} + 6 x + 1

Subtract $(8 - 6 x + x^{2} - 7 x^{3} + x^{5})$ from $(x^{4} - 6 x^{3} + x^{2} - 3 x + 1)$ .

- 7 x^{3} + 4 x

- 2 x^{3} + 8 x

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