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Question

Subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).

A
3a+2b+4c
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B
2a2b+4c
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C
3a4b2c
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D
2a+3b+4c
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Solution

The correct option is D 2a+3b+4c
It is instructed to subtract (2a3b+4c) from the sum of (a+3b4c),(4ab+9c) and (2b+3ca).

So, First we will do the sum of the three given polynomials,
Sum =(a+3b4c)+(4ab+9c)+(2b+3ca)
=(a+4aa)+(3bb2b)+(4c+9c+3c)
=4a+8c
Now, we can perform the subtraction,
Required difference
=(4a+8c)(2a3b+4c)
=4a+8c2a+3b4c
=2a+3b+4c

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