Subtract $2 x^{2} + 2 y^{2} - 6$ from $3 x^{2} - 7 y^{2} + 9$

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Solution

Given expressions are $2 x^{2} + 2 y^{2} - 6$ and $3 x^{2} - 7 y^{2} + 9$ .

To find out,
The result when we subtract $2 x^{2} + 2 y^{2} - 6$ from $3 x^{2} - 7 y^{2} + 9$ .

On subtracting, we get:
$(3 x^{2} - 7 y^{2} + 9) - (2 x^{2} + 2 y^{2} - 6)$

$= 3 x^{2} - 7 y^{2} + 9 - 2 x^{2} - 2 y^{2} + 6$

On combining the like terms, we get:

$3 x^{2} - 2 x^{2} - 7 y^{2} - 2 y^{2} + 9 + 6$

$= x^{2} - 9 y^{2} + 15$

Hence, the result when we subtract $2 x^{2} + 2 y^{2} - 6$ from $3 x^{2} - 7 y^{2} + 9$ is $x^{2} - 9 y^{2} + 15$ .

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Subtract 2x2+2y2−6 from 3x2−7y2+9

Subtract $2 x^{2} + 2 y^{2} - 6$ from $3 x^{2} - 7 y^{2} + 9$