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Question

Subtract (2x4y+3z) from the sum of (x+3y4z),(2x+yz) and (2x+3yz).

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Solution

(x+3y4z)+(2x+yz)+(2x+3yz)(2x4y+3z)
=(x+2x+3y+y4zz)+(2x+3yz)(2z4y+3z)
=(3x+4y5z)+(2x+3yz)(2x4y+3z)
=(x+7y6z)(2x4y+3z)
=x2x+7y+4y6z3z
=x+11y9z
Ans is (x+11y9z)

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