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Byju's Answer
Standard VII
Mathematics
Solving an Equation
Subtract 3a...
Question
Subtract
3
a
−
2
b
+
4
c
from the sum of
−
2
a
+
b
−
5
c
and
3
a
−
2
b
+
c
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Solution
Sum of
−
2
a
+
b
−
5
c
and
3
a
−
2
b
+
c
=
−
2
a
+
b
−
5
c
+
3
a
−
2
b
+
c
=
a
−
b
−
4
c
Subtracting
3
a
−
2
b
+
4
c
from
a
−
b
−
4
c
=
a
−
b
−
4
c
−
(
3
a
−
2
b
+
4
c
)
=
a
−
b
−
4
c
−
3
a
+
2
b
−
4
c
=
−
2
a
+
b
−
8
c
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