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Question

Subtract 3a2b+4c from the sum of 2a+b5c and 3a2b+c

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Solution

Sum of 2a+b5c and 3a2b+c = 2a+b5c+3a2b+c
= ab4c

Subtracting 3a2b+4c from ab4c

= ab4c(3a2b+4c)

=ab4c3a+2b4c

=2a+b8c

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