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Question
Subtract:
3a−5b+c+2d from 7a−3b+c−2d
3a−5b+c+2d from 7a−3b+c−2d
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Solution
Subtraction of (3a−5b+c+2d) from
7a−3b+c−2d
=(7a−3b+c−2d)−(3a−5b+c+2d)
=(7a−3b+c−2d)−3a+5b−c−2d
=(7a−3a)+(−3b+5b)+(c−c)
+(−2d−2d)
=(7−3)a+(−3+5)b+(1−1)c+(−2−2)d
=4a+2b+0−4d
=4a+2b−4d
Hence, the required answer is 4a+2b−4d.
7a−3b+c−2d
=(7a−3b+c−2d)−(3a−5b+c+2d)
=(7a−3b+c−2d)−3a+5b−c−2d
=(7a−3a)+(−3b+5b)+(c−c)
+(−2d−2d)
=(7−3)a+(−3+5)b+(1−1)c+(−2−2)d
=4a+2b+0−4d
=4a+2b−4d
Hence, the required answer is 4a+2b−4d.
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