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Question

Subtract 3a(a2b+3c) from 4a(5a+2b3c)

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Solution

Subtraction of 3a(a2b+3c) from 4a(5a+2b3c)
4a(5a+2b3c)=20a2+8ab12ac
3a(a2b+3c)=3a26ab+9ac
Subtract, 20a2+8ab12ac(3a2+9ac+6ab)
=20a2+8ab12ac3a29ac+6ab
=17a2+14ab21ac
Hence, the answer is 17a2+14ab21ac.

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