wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Subtract: 3a(a+b+c)2(ab+c) from 4c(a+b+c)

A
3a22b2+4c2ab+6bc+7ac
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3a2+2b2+4c2ab+6bc7ac
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
ac+4bc+4c23a2ab+2c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
ac+4bc+4c2+3a2ab+2c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 3a2+2b2+4c2ab+6bc7ac
3a(a+b+c)2b(a+b+c)

3a(a+b+c)2b(a+b+c)=3a2+3ab+3ac(2ab+2b2+2bc)

3a(a+b+c)2b(a+b+c)=3a2+3ab+3ac2ab2b22bc

3a(a+b+c)2b(a+b+c)=3a22b2+ab+3ac2bc

Required difference 4c(a+b+c)(3a22b2+ab+3ac2bc)

4c(a+b+c)(3a22b2+ab+3ac2bc)=4ac+4bc+4c23a2+2b2ab3ac+2bc

4c(a+b+c)(3a22b2+ab+3ac2bc)=3a2+2b2+4c27ac+6bcab


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Addition and Subtraction of Algebraic Expression
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon