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Question

Subtract: 3a(a+b+c)2(ab+c) from 4c(a+b+c)

A
3a22b2+4c2ab+6bc+7ac
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B
3a2+2b2+4c2ab+6bc7ac
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C
ac+4bc+4c23a2ab+2c
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D
ac+4bc+4c2+3a2ab+2c
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Solution

The correct option is D 3a2+2b2+4c2ab+6bc7ac
3a(a+b+c)2b(a+b+c)

3a(a+b+c)2b(a+b+c)=3a2+3ab+3ac(2ab+2b2+2bc)

3a(a+b+c)2b(a+b+c)=3a2+3ab+3ac2ab2b22bc

3a(a+b+c)2b(a+b+c)=3a22b2+ab+3ac2bc

Required difference 4c(a+b+c)(3a22b2+ab+3ac2bc)

4c(a+b+c)(3a22b2+ab+3ac2bc)=4ac+4bc+4c23a2+2b2ab3ac+2bc

4c(a+b+c)(3a22b2+ab+3ac2bc)=3a2+2b2+4c27ac+6bcab


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