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Byju's Answer
Standard VI
Mathematics
Coefficient
Subtract 3 x-...
Question
Subtract 3x − 4y − 7z from the sum of x − 3y + 2z and − 4x + 9y − 11z.
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Solution
Let first add the expressions
x
-
3
y
+
2
z
and
-
4
x
+
9
y
-
11
z
. We get:
x
-
3
y
+
2
z
+
-
4
x
+
9
y
-
11
z
=
x
-
3
y
+
2
z
-
4
x
+
9
y
-
11
z
=
x
-
4
x
-
3
y
+
9
y
+
2
z
-
11
z
(Collecting like terms)
=
-
3
x
+
6
y
-
9
z
(Combining like terms)
Now, subtracting the expression
3
x
-
4
y
-
7
z
from the above sum; we get:
-
3
x
+
6
y
-
9
z
-
3
x
-
4
y
-
7
z
=
-
3
x
+
6
y
-
9
z
-
3
x
+
4
y
+
7
z
=
-
3
x
-
3
x
+
6
y
+
4
y
-
9
z
+
7
z
(Collecting like terms)
=
-
6
x
+
10
y
-
2
z
(Combining like terms)
Thus, the answer is
-
6
x
+
10
y
-
2
z
.
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Similar questions
Q.
Solve the following equations:
4
x
−
3
y
+
2
z
=
40
5
x
+
9
y
−
7
z
=
47
9
x
+
8
y
−
3
z
=
97
Q.
Subtract
3
x
(
x
−
4
y
+
5
z
)
from
4
x
(
2
x
−
3
y
+
10
z
)
Q.
Show that each of the following systems of linear equations is consistent and also find their solutions:
(i) 6x + 4y = 2
9x + 6y = 3
(ii) 2x + 3y = 5
6x + 9y = 15
(iii) 5x + 3y + 7z = 4
3x + 26y + 2z = 9
7x + 2y + 10z = 5
(iv) x − y + z = 3
2x + y − z = 2
−x −2y + 2z = 1
(v) x + y + z = 6
x + 2y + 3z = 14
x + 4y + 7z = 30
(vi) 2x + 2y − 2z = 1
4x + 4y − z = 2
6x + 6y + 2z = 3
Q.
State True or False:
Addition of
8
x
−
3
y
+
7
z
,
−
4
x
+
5
y
−
4
z
,
−
x
−
y
−
2
z
is
3
x
+
y
+
z
.
Q.
Solve the following system of equations by matrix method:
(i)
x
+
y
−
z
= 3
2
x
+ 3
y
+
z
= 10
3
x
−
y
− 7
z
= 1
(ii)
x
+
y
+
z
= 3
2
x
−
y
+
z
= − 1
2
x
+
y
− 3
z
= − 9
(iii) 6
x
− 12
y
+ 25
z
= 4
4
x
+ 15
y
− 20
z
= 3
2
x
+ 18
y
+ 15
z
= 10
(iv) 3
x
+ 4
y
+ 7
z
= 14
2
x
−
y
+ 3
z
= 4
x
+ 2
y
− 3
z
= 0
(v)
2
x
-
3
y
+
3
z
=
10
1
x
+
1
y
+
1
z
=
10
3
x
-
1
y
+
2
z
=
13
(vi) 5
x
+ 3
y
+
z
= 16
2
x
+
y
+ 3
z
= 19
x
+ 2
y
+ 4
z
= 25
(vii) 3
x
+ 4
y
+ 2
z
= 8
2
y
− 3
z
= 3
x
− 2
y
+ 6
z
= −2
(viii) 2
x
+
y
+
z
= 2
x
+ 3
y
−
z
= 5
3
x
+
y
− 2
z
= 6
(ix) 2
x
+ 6
y
= 2
3
x
−
z
= −8
2
x
−
y
+
z
= −3
(x)
x
−
y
+
z
= 2
2
x
−
y
= 0
2
y
−
z
= 1
(xi) 8
x
+ 4
y
+ 3
z
= 18
2
x
+
y
+
z
= 5
x
+ 2
y
+
z
= 5
(xii)
x
+
y
+
z
= 6
x
+ 2
z
= 7
3
x
+
y
+
z
= 12
(xiii)
2
x
+
3
y
+
10
z
=
4
,
4
x
-
6
y
+
5
z
=
1
,
6
x
+
9
y
-
20
z
=
2
;
x
,
y
,
z
≠
0
(xiv)
x
−
y
+ 2
z
= 7
3
x
+ 4
y
− 5
z
= −5
2
x
−
y
+ 3
z
= 12
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