Question

$\text{Subtract}$ $4p^{2}q-3pq+5p{q}^2-8p+7q-10$ $\text{from}$
$18-3p-11q+5pq-2p{q}^2+5p^{2}q$

Answer 1

⇒4p2q−3pq+5pq2−8p+7q−10=x \Rightarrow 4p^{2}q-3pq+5pq^{2}-8p+7q-1Lert

18−3p−11q+5pq−2pq2+5p2q=y 18-3p-11q+5pq-2pq^{2}+5p^{2}q = y

$\text{Let}$ $x=4p^{2}q-3pq+5p{q}^2-8p+7q-10$

$\text{and,}$ $y=18-3p-11q+5pq-2p{q}^2+5p^{2}q$

$y-x=(18-3p-11q+5pq-2p{q}^2+5p^{2}q)-(4p^{2}q-3pq+5p{q}^2-8p+7q-10)$

$=18-3p-11q+5pq-2p{q}^2+5p^{2}q-4p^{2}q+3pq-5p{q}^2+8p-7q+10$

$=(5p^{2}q-4p^{2}q)+(-5p{q}^2-2p{q}^2)+(5pq+3pq)+(8p-3p)+(-11q-7q)+(18+10)$

$=p^{2}q-7p{q}^2+8pq+5p-18q+28$

$\text{Therefore, the required difference is}$ $p^{2}q-7p{q}^2+8pq+5p-18q+28$