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Question

Subtract 4p2q−3pq+5pq2−8p+7q−10 from 18−3p−11q+5pq−2q2+5p2q

A
28+5p18q+8pq2q2+p2q5pq2
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B
8+11p18q+8pq2q2+p2q5pq2
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C
285p+18q8pq+2q2p2q+5pq2
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D
none
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Solution

The correct option is A 28+5p18q+8pq2q2+p2q5pq2
We subtract the given expression 4p2q3pq+5pq28p+7q10 from 183p11q+5pq2q2+5p2q as shown below:

(183p11q+5pq2q2+5p2q)(4p2q3pq+5pq28p+7q10)=183p11q+5pq2q2+5p2q4p2q+3pq5pq2+8p7q+10=(18+10)+(3p+8p)+(11q7q)+(5pq+3pq)2q2+(5p2q4p2q)5pq2(Combiningliketerms)=28+5p18q+8pq2q2+p2q5pq2

Hence, (183p11q+5pq2q2+5p2q)(4p2q3pq+5pq28p+7q10)=28+5p18q+8pq2q2+p2q5pq2.

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