Subtract $41 - a b + 3 d + 12$ from $12 a - 9 a b + 5 b - 3$ .

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Solution

We have
$(12 a - 9 a b + 5 b - 3) - (41 - 1 a b + 3 d + 12)$
$= 12 a - 8 a b + 5 b - 44 - 3 d - 12$
$= 12 a - 8 a b + 5 b - 56 - 3 d$
$= 12 a + 5 b - 3 d - 8 a b - 56$
It is the required answer.

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Similar questions

Q. Subtract

4 a - 7 a b + 3 b + 12

from

12 a - 9 a b + 5 b - 3

Q. Question 4(i)
Subtract 4a - 7 ab + 3b +12 from 12 a - 9 ab + 5b - 3

(a) Subtract 4a − 7ab + 3b + 12 from 12a − 9ab + 5b − 3

(b) Subtract 3xy + 5yz − 7zx from 5xy − 2yz − 2zx + 10xyz

Subtract:
(i) $4 a - 7 a b + 3 b + 12$ from $12 a - 9 a b + 5 b - 3$
(ii) $3 x y + 5 y z - 7 x z$ from $5 x y - 2 y z - 2 x z + 10 x y z$
(iii) $4 p^{2} q - 3 p q + 5 p q^{2} - 8 p + 7 q - 10$ from $18 - 3 p - 11 q + 5 p q - 2 p q^{2} + 5 p^{2} q$

Q. (i)Subtract

4 a - 7 a b + 3 b + 12

from

12 a - 9 a b + 5 b - 3

.
(ii)Subtract

3 x y + 5 y z - 7 z x

from

5 x y - 2 y z - 2 z x + 10 x y z

.
(iii)Subtract

4 p^{2} q - 3 p q + 5 p q^{2} - 8 p + 7 q - 10

from

18 - 3 p - 11 q + 5 p q - 2 p q^{2} + 5 p^{2} q

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Subtract 41−ab+3d+12 from 12a−9ab+5b−3.

We have(12a−9ab+5b−3)−(41−1ab+3d+12)=12a−8ab+5b−44−3d−12=12a−8ab+5b−56−3d=12a+5b−3d−8ab−56It is the required answer.

Subtract $41 - a b + 3 d + 12$ from $12 a - 9 a b + 5 b - 3$ .

We have
$(12 a - 9 a b + 5 b - 3) - (41 - 1 a b + 3 d + 12)$
$= 12 a - 8 a b + 5 b - 44 - 3 d - 12$
$= 12 a - 8 a b + 5 b - 56 - 3 d$
$= 12 a + 5 b - 3 d - 8 a b - 56$
It is the required answer.