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Question

Subtract 4a2 + 5b2 − 6c2 + 8 from 2a2 − 3b2 − 4c2 − 5.

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Solution

2a2 - 3b2 -4c2 -5 -( 4a2 +5b2 -6c2 +8)= 2a2 - 3b2 -4c2 -5 -4a2 -5b2 + 6c2 -8= 2a2 -4a2 - 3b2 -5b2-4c2 +6c2-5 -8= -2a2-8b2+2c2-13

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