Subtract 4p2q−3pq+5pq2−8p−7q−10 from 18−3p+11q+5pq−2pq2+5p2q
A
pq2−7p2q+8pq+18q+5p+28
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B
p2q−7pq2+8pq+18p+5q+28
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C
pq2−7p2q+8pq+18p+5q+28
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D
p2q−7pq2+8pq+18q+5p+28
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Solution
The correct option is Cp2q−7pq2+8pq+18q+5p+28 Subtract 4p2q−3pq+5pq2−8p−7q−10 from 18−3p+11q+5pq−2pq2+5p2q =18−3p+11q+5pq−2pq2+5p2q−(4p2q−3pq+5pq2−8p−7q−10) =18−3p+11q+5pq−2pq2+5p2q−4p2q+3pq−5pq2+8p+7q+10 =28+5p+18q+8pq−7pq2+p2q