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Question

Subtract 4p2q−3pq+5pq2−8p−7q−10 from 18−3p+11q+5pq−2pq2+5p2q

A
pq27p2q+8pq+18q+5p+28
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B
p2q7pq2+8pq+18p+5q+28
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C
pq27p2q+8pq+18p+5q+28
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D
p2q7pq2+8pq+18q+5p+28
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Solution

The correct option is C p2q7pq2+8pq+18q+5p+28
Subtract 4p2q3pq+5pq28p7q10 from 183p+11q+5pq2pq2+5p2q
=183p+11q+5pq2pq2+5p2q(4p2q3pq+5pq28p7q10)
=183p+11q+5pq2pq2+5p2q4p2q+3pq5pq2+8p+7q+10
=28+5p+18q+8pq7pq2+p2q

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