Given: Subtract 5x2−4y2+6y−3 from 7x2−4xy+8y2+5x−3y=7x2−4xy+8y2+5x−3y−(5x2−4y2+6y−3)=7x2−4xy+8y2+5x−3y−5x2+4y2−6y+3=(7x2−5x2)−4xy+(8y2+4y2)+5x+(−3x−6y)+3=2x2−4xy+12y2+5x−9y+3 is the required answer.
Question 82 (ii)
Subtract
6x2−4xy+5y2 from 8y2+6xy−3x2